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STD 11 - 13. oscillations — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 13. oscillations4 Marks
MCQ
What will be the force constant of the spring system shown in the figure
  • A
    $\frac{{{K_1}}}{2} + {K_2}$
  • ✓
    ${\left[ {\frac{1}{{2{K_1}}} + \frac{1}{{{K_2}}}} \right]^{ - 1}}$
  • C
    $\frac{1}{{2{K_1}}} + \frac{1}{{{K_2}}}$
  • D
    ${\left[ {\frac{2}{{{K_1}}} + \frac{1}{{{K_1}}}} \right]^{ - 1}}$
✓

Answer

Correct option: B.
${\left[ {\frac{1}{{2{K_1}}} + \frac{1}{{{K_2}}}} \right]^{ - 1}}$
b
(b)In series combination
$\frac{1}{{{k_S}}} = \frac{1}{{2{k_1}}} + \frac{1}{{{k_2}}}$
==> ${k_S} = {\left[ {\frac{1}{{2{k_1}}} + \frac{1}{{{k_2}}}} \right]^{ - 1}}$

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