MCQ
What will be the grouping of cells when the current in the circuit is $\frac{\text{ne}}{(\text{R+nr})}$?
- AParallel grouping.
- ✓Series grouping.
- CMixed grouping.
- DWhen there is no grouping.
✓
Answer
Correct option: B.
Series grouping.
When n identical cells, each of emf $' e\ '$ and internal resistance $' r\ '$ are connected to the external resistance $' R\ '$ in series, its called series grouping. In series grouping $e _{ eq }= ne$ and $r _{ eq }= nr$ Therefore, current in the circuit $( l )=\frac{ ne }{( R + nr )}$
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