Question
What will be the value of maximum and minimum capacitances oblained from the combinations of three capacitors. each of which has a capacitance of $6 \mu F$ ?
✓
Answer
Maximum capacitance $=6 \mu F+6 \mu F+6 \mu F$
$ =18 \mu F $
Minimum capacitance $ \frac{1}{C}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}$
$=\frac{3}{6}=\frac{1}{2}$
$C=2 \mu F $
$ =18 \mu F $
Minimum capacitance $ \frac{1}{C}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}$
$=\frac{3}{6}=\frac{1}{2}$
$C=2 \mu F $
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