What would be magnetic moment of $Gd^{+3 }(Z = 64)$ ?
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Electronic configuration of $[Gd]^{3+ }: [Xe]4f^7$
Hence number of unpaired electron $n = 7$
Hence, magnetic moment $=\sqrt{\text{n(n+2)}}=\sqrt{63}=7.9\text{BM}$
Hence number of unpaired electron $n = 7$
Hence, magnetic moment $=\sqrt{\text{n(n+2)}}=\sqrt{63}=7.9\text{BM}$
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