When a large bubble rises from the bottom of a lake to the surface. Its radius doubles. If atmospheric pressure is equal to that of column of water height $H$, then the depth of lake is
AIIMS 1995, Diffcult
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(c) ${P_1}{V_1} = {P_2}{V_2}$==> $({P_0} + h + g) \times \frac{4}{3}\pi {r^3}$=${P_0} \times \frac{4}{3}\pi {(2r)^3}$
Where, $h = $ depth of lake
==> $h\rho g = 7{P_0}$==> $h = 7 \times \frac{{H\rho g}}{{\rho g}} = 7H.$
Where, $h = $ depth of lake
==> $h\rho g = 7{P_0}$==> $h = 7 \times \frac{{H\rho g}}{{\rho g}} = 7H.$
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