When a load of $10 \,kg$ is suspended on a metallic wire, its length increase by $2 \,mm$. The force constant of the wire is $........ N / m$
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Force constant $(K)=\frac{\text { Force }}{\text { Elongation }}=\frac{F}{\Delta x}$
$\left\{\begin{array}{l}F=10 \,kg =100 \,N \\ \Delta x=2 \,mm =0.002 \,m \end{array}\right.$
Substituting values
$K=\frac{100}{0.002}=5 \times 10^4 \,N / m$
$\left\{\begin{array}{l}F=10 \,kg =100 \,N \\ \Delta x=2 \,mm =0.002 \,m \end{array}\right.$
Substituting values
$K=\frac{100}{0.002}=5 \times 10^4 \,N / m$
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