When a proton is accelerated through $1\,V$, then its kinetic energy will be.....$eV$
A$1840$
B$13.6$
C$1$
D$0.54$
AIPMT 1999, Easy
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C$1$
c $\Delta \,KE = qV = eV = e \times 1 = 1\,eV$
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