Question
  1. When an AC source is connected to an ideal capacitor, show that the average power supplied by the source over a complete cycle is zero.
  2. A bulb is connected in series with a variable capacitor and an A.C. source as shown. What happens to the brightness of the bulb when the key is the capacitor is gradually reduced?

Answer

  1. Let the applied voltage be

$\text{V}= \text{V}_{o}\sin\omega\text{t}$

The current through an ideal capacitor, would then be

$\text{I} = \text{I}_{o}\sin(\omega\text{t} + \frac{\pi}{2}) = \text{I}_{0}\cos\omega\text{t}$

$\therefore\text{P}_{inst} = \text{VI}$

$\therefore\text{P}_{AV} = \frac{1}{\text{T}}\int^{T}_{0}\text{VIdt}$

$\therefore\text{P}_{AV} = \frac{\text{V}_{0}\text{I}_{0}}{2}\langle\sin2\omega\text{t}\rangle$

$=0.$

  1. $\text{X}_{c} = \frac{1}{\omega\text{C}}$

$\therefore\text{X}_{c}$ increases as C decreases. Hence, with decreasing C, the brightness of the bulb would decrease.

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