MCQ
When $CH_3CH_2CH_2CHCl_2$ is treated with $2\, gram$ equivalent $NaNH_2$, the product formed is
- ✓$C{H_3}C{H_2}C \equiv CH$
- B$C{H_3}C{H_2}-CH = C{H_2}$
- C

- D



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$(i)$ Chlorobenzene
$(ii)$ Benzene
$(iii)$ Anilinium chloride
$(iv)$ Toluene