MCQ
When $CH_3CH_2CH_2CHCl_2$ is treated with $2\, gram$ equivalent $NaNH_2$, the product formed is
- ✓$C{H_3}C{H_2}C \equiv CH$
- B$C{H_3}C{H_2}-CH = C{H_2}$
- C
- D
✓
Answer
Correct option: A.
$C{H_3}C{H_2}C \equiv CH$
a
$CH_3-CH_2-CH_2-CHCl_2$ $\xrightarrow{{NaN{H_2}}}C{H_3} - C{H_2} - C \equiv CH$
$CH_3-CH_2-CH_2-CHCl_2$ $\xrightarrow{{NaN{H_2}}}C{H_3} - C{H_2} - C \equiv CH$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
For the following Assertion and Reason, the correct option is
→Assertion : The $pH$ of water increases with increase in temperature.
Reason : The dissociation of water into $H^+$ and $OH^-$ is an exothermic reaction.
$pH$ of human blood is $7.4$ . Then ${H^ + }$ concentration will be
→Conditions of standard state used in thermochemistry is
The most basic among these hydroxides, is
Let the solubility of an aqueous solution of $Mg{(OH)_2}$ be $x$ then its ${k_{sp}}$ is
→Which types of isomerism is shown by $2, 3-$ dichlorobutane
→The total number of electrons that can be accommodated in all the orbitals having principal quantum number $2$ and azimuthal quantum number $1$ is
→Two electrons occupying the same orbital are distinguished by
The separation of a racemic mixture into pure enantiomers is termed as
Compare stability of free radicals
→$(1)$ $C{H_3} - \mathop {CH}\limits^ \bullet C{H_3}$
$(2)$ (fig.)
$(3)$ $\mathop {C{H_2}}\limits^ \bullet - CH{(C{H_3})_2}$
$(4)$ $\mathop {C{H_2}}\limits^ \bullet - C{H_3}$