MCQ
When chloroform hydrolysed with $KOH$. Then the final product is
- A$HCOOH$
- ✓$HCOOK$
- C$CH_3OH$
- D$(CHCOOK)_2$
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$CH_3-CH_2-OH$ $\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)$ $\xrightarrow{{B{r_2}/KOH}}(C)$
$(C)$ will be :
$(A)$ $NH _4 NO _3$ $(B)$ $\left( NH _4\right)_2 Cr _2 O _7$ $(C)$ $Ba \left( N _3\right)_2$ $(D)$ $Mg _3 N _2$