MCQ
When Cu2+ ion is treated with KI, a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is formed. X and Y respectively are
  • A
    $X = Cul _2 Y = Na _2 S_4 O _6$
  • B
    $X = Cu _2 l _2 Y = Na _2 S_4 O _5$
  • C
    $X = Cul _2 Y = Na _2 S_4 O _3$
  • D
    $X = Cu _2 l _2 Y = Na _2 S_4 O _6$

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