MCQ
When $H_2SO_4$ react with $PCl_5$ the obtained product is/are
- ✓$SO_2Cl_2$
- B$POCl_3$
- C$HCl$
- DAll of these
✓
Answer
Correct option: A.
$SO_2Cl_2$
a
Hydrides of group $16^{\text {th }}$
Hydrides of group $16^{\text {th }}$
$H _{2} O \,\,\,\,\,\,\,\,\,\,\,\,\,\, \underbrace{ H _{2} S \,\,\, H _{2} Se \,\,\, H _{2} Te}$
$\,\,$H-Bond $\,\,\,\,\,\,\,\,\,\,$ VMA $\propto$ mol.wt.
$\text { B.P. } \rightarrow H _{2} S < H _{2} Se < H _{2} Te < H _{2} O$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Diazo coupling is useful to prepare some:
$PtCl_4 . 6H_2O$ can exist as a hydrated complex. Its $1\,molal$ aq. solution has depression in freezing point of $3.72$. Assume $100\%$ ionisation and $K_f\,(H_2O) = 1.86\,^oC\,mol^{-1}\,kg$, then complex is
→Froth floatation process for the concentration of ores is an illustration of physical phenomenon of:
The $\text{EMF}$ of a galvanic cell is determined by using a:
→The rate of reaction between $A$ and $B$ increases by a factor of $100,$ when the concentration of $A$ is increased $10$ folds. The order of reaction with respect to $A$ is
→By which of the following, poisoning of lead in the body can be removed?
Which of the following technique uses high temperature to convert ore into raw metals?
Decreasing order of basicity is
→(1) $C{H_3}CON{H_2}$
(2) $C{H_3}C{H_2}N{H_2}$
(3) $ Ph-C{H_2}CON{H_2}$
Unknown $(A)$ in the reaction
→When two molecules of acetaldehyde condense in the presence of dilute alkali, it forms