MCQ
When lead nitrate is heated, it gives
- ✓$N{O_2}$
- B$NO$
- C${N_2}{O_5}$
- D${N_2}O$
$2Pb{(N{O_3})_2} \to 2PbO + 4N{O_2} + {O_2}$
So nitric oxide ${N_2}O$ is produced.
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$(i)\,\,(CH_3)_2CH-CH_2Br \xrightarrow{{{C_2}{H_5}OH}} (CH_3)_2CH-CH_2OC_2H_5 + HBr$
$(ii)\,\,(CH_3)_2CH-CH_2-Br \xrightarrow{{{C_2}{H_5}{O^- }}} (CH_3)_2CH-CH_2OC_2H_5 + Br^-$
The mechanisms of reaction $(i)$ and $(ii)$ are respectively