- A$Pb{O_2}$ is dissolved
- B$PbS{O_4}$ is deposited on lead electrode
- ✓${H_2}S{O_4}$ is regenerated
- DLead is deposited on lead electrode
$P b_{(s)}+P b O_{2(s)}+2 H_{2} S O_{4(a q)} \rightarrow 2 P b S O_{4(s)}+2 H_{2} O_{(l)}$
$\rightarrow$ During discharge, $H_{2} S O_{4}$ is consumed and its density decreases.
$\rightarrow$ Fully charged cell gives a potential of about $2 V$. When the cell potential reduces to about $1.8 V$ it should be recharged.
Net cell reaction during recharge:-
$2 P b S O_{4(s)}+2 H_{2} O_{(l)} \rightarrow P b_{(s)}+P b O_{2(s)}+2 H_{2} S O_{4(a q)}$
$\rightarrow$ The concentration of $H_{2} S O_{4}$ increases as it is generated.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

| $column 1$ | $column 2$ | $column 3$ |
| $(I)$ $1$s orbital | $(i)$ $\psi_{n, l, m_l} \propto\left(\frac{Z}{a_0}\right)^{\frac{3}{2}} e^{-\left(\frac{Z r}{a_0}\right)}$ | $image$ |
| ($II$) $2 \mathrm{~s}$ orbital | $(ii)$ One radial node | $(Q)$ Probability density at nucleus $\propto \frac{1}{a_0^3}$ |
| $(III)$ $2 p_z$ orbital | $(iii)$ $\psi_{n, l m_l} \propto\left(\frac{Z}{a_0}\right)^{\frac{5}{2}} r e^{-\left(\frac{Z r}{2 a_0}\right)} \cos \theta$ | $(R)$ Probability density is maximum at nucleus |
| $(IV)$ $3 \mathrm{~d}_{\mathrm{z}}^2$ orbital | $(iv)$ $x y$-plane is a nodal plane | $(S)$ Energy needed to excite electron from $n=2$ state to $n=4$ state is $\frac{27}{32}$ times the energy needed to excite electron from $n=2$ state to $n=6$ state |
($1$) For the given orbital in Column $1$, the only $CORRECT$ combination for any hydrogen-like species is
$[A] (IV) (iv) (R)$ $[B] (II) (ii) (P)$ $[C] (III) (iii) (P)$ $[D] (I) (ii) (S)$
($2$) For $\mathrm{He}^{+}$ion, the only INCORRECT combination is
$[A] (II) (ii) (Q)$ $[B] (I) (i) (S)$ $[C] (I) (i) (R)$ $[D] (I) (iii) (R)$
($3$) For hydrogen atom, the only $CORRECT$ combination is
$[A] (I) (iv) (R)$ $[B] (I) (i) (P)$ $[C] (II) (i) (Q)$ $[D] (I) (i) (S)$
Give the answer quetion ($1$) ($2$) and ($3$)
(Molecular mass of $CHCl_3 = 119.5 \,u$ and molecular mass of $CH_2Cl_2 = 85\, u$)