MCQ
When methyl bromide is heated with $Zn$ it gives
- A$C{H_4}$
- ✓${C_2}{H_6}$
- C${C_2}{H_4}$
- D$C{H_3}OH$
✓
Answer
Correct option: B.
${C_2}{H_6}$
b
(b)$C{H_3}Br + Zn + BrC{H_3}\xrightarrow{\Delta }{C_2}{H_6} + ZnB{r_2}$
(b)$C{H_3}Br + Zn + BrC{H_3}\xrightarrow{\Delta }{C_2}{H_6} + ZnB{r_2}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Number of moles of $SnCl_2$ required for the reduction of $1$ mole of $K_2Cr_2O_7$ into $Cr_2O_3$ is (in acidic medium)
→Incorrect statement for the given configuration $[Xe]\,4f^7\,5d^1\,6s^2$
→Among $H_2O, H_2S, H_2Se$ and $H_2Te$. The one with the highest boiling point is
→The $\text{CFSE}$ for octahedral $\left[\mathrm{CoCl}_6\right]^{4-} 18,000 \ cm^{-1}$ . The $\text{CFSE}$ for tetrahedral $\left[\mathrm{CoCl}_4\right]^{2-}$ will be:
→(major) Product $(A)$ is
→Aqueous solution of ferric chloride is
Williamson's synthesis is used for the preparation of
For a $d ^{4}$ metal ion in an octahedral field, the correct electronic configuration is:
→$2-$ hexene $\longrightarrow$ Products
→The two products formed in above reaction are -
It is found in phosphorus and nitrogen: