Download App

4. Chemical bonding and molecular structure — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry4. Chemical bonding and molecular structure1 Mark
MCQ
When $NaCl$ is dissolved in water the sodium ion becomes
  • A
    Oxidised
  • B
    Reduced
  • C
    Hydrolysed
  • ✓
    Hydrated
✓

Answer

Correct option: D.
Hydrated
(d) $NaCl + {H_2}O \to NaOH + HCl$ Sodium ion hydrated in water.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 4. Chemical bonding and molecular structure→4. Chemical bonding and molecular structure — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Ionic reactions with organic compounds proceed through:

$(A)$ Homolytic bond cleavage

$(B)$ Heterolytic bond cleavage

$(C)$ Free radical formation

$(D)$ Primary free radical

$(E)$ Secondary free radical

Choose the correct answer from the options given below:

→
Air containing $79\%$ of nitrogen and $21\%$ of oxygen by volume is heated at $2200\, K$ and $1$ atm until equilibrium is established according to the reaction
$N_2(g) + O_2(g)  \rightleftharpoons  2NO(g)$
If the $K_p$ of the reaction is $1.1\times10^{-3}$, calculate the amount of nitric oxide produced in terms of volume percent.
→
Electrovalent bond formation depends on
→
$0.1\,M$ $CH_3COOH$ is titrated against $0.1\,M$ $NaOH$. What would be the difference in $pH$ between $1/4$ and $3/4$ stages of neutralisation of acid
→
${H_2}{C_2}{O_4}$ $\xrightarrow{\Delta }$ gas $(A)$ + gas $(B)$ + liquid $(C)$. 

Gas $(A)$ burns with a blue flame and is oxidised to gas $(B)$

Gas $(A) + Cl_2 \to (D)$

$A, B$ and $D$ are

→
Beryllium’s fourth electron will have the four quantum numbers :
→
What is the molecular formula of the alkane, the $5.6 \,litre$ of which weight $11 \,g$ at $STP$
→
${M^{ + 3}}$ ion loses $3{e^ - }$. Its oxidation number will be
→
The number of radial nodes of $ 3s$ and $2p$  orbitals are respectively.
→
Production of iron in blast furnace follows the following equation

$Fe _{3} O _{4}( s )+4 CO ( g ) \rightarrow 3 Fe ( l )+4 CO _{2}( g )$

when $4.640 \,kg$ of $Fe _{3} O _{4}$ and $2.520 \,kg$ of $CO$ are allowed to react then the amount of iron (in $g$ ) produced is $....$

[Given : Molar Atomic mass $\left( g\, mol ^{-1}\right): Fe =56$

Molar Atomic mass $\left( g \,mol ^{-1}\right): 0=16$

Molar Atomic mass $\left( g\, mol ^{-1}\right):= C =12$

→