MCQ
${M^{ + 3}}$ ion loses $3{e^ - }$. Its oxidation number will be
  • A
    $0$
  • B
    $+3$
  • $+6$
  • D
    $-3$

Answer

Correct option: C.
$+6$
(c) $2$ $×$ No. of ${e^ - }$ losses = Oxi. no.

$2 \times 3{e^ - } = + 6$.

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