Question
When pressure increases by 1%, what is the percentage decrease in the volume of a gas, if Boyle's law is obeyed?
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Answer
We know PV = constant If P is increased by 1%, then volume will decrease. $\therefore$ (P + 0.01P)(V - dV) = PV -PdV + 0.01PV - 0.01PdV = 0 -PdV(1 + 0.01) = -0.01PV
$\therefore\frac{\text{dV}}{\text{V}}=\frac{0.01}{1.01}$
% variation in volume = 0.98Need a full question paper?
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