- AHelium.
- BArgon.
- COxygen.
- DCarbon dioxide.
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$\text{C}_{\text{v}}=\frac{\text{Du}}{\text{Dt}}=(\frac{3}{2})\text{R}$
For an ideal gas, Cp - Cv = R Where Cp is the molar specific heat at constant pressure. Thus, $\text{C}_\text{P} =(\frac{5}{2})\text{R}$ The ratio of specific heats IS $\gamma=\frac{\text{cp}}{\text{cv}}=\frac{5}{3}$ Diatomic Gases: a diatomic molecule treated as a rigid rotator, like a dumbbell, has 5 degrees of freedom: 3 translational and 2 rotational. Using the law of equipartition of energy, the total internal energy of a mole of such a gas is $\text{U}=\frac{5}{2}\text{RT}$ The molar specific heat at constant volume cv is given by$\text{Cv}=\frac{\text{DU}}{\text{DT}}=(\frac{5}{2})\text{R}$
For an ideal gas, Cp – Cv = R Where Cp is the molar specific heat at constant pressure. Thus, $\text{C}_\text{P} =(\frac{7}{2})\text{R}$ The ratio of specific heats IS $γ( \text{for rigid diatomic)}=\frac{\text{C}_\text{P}}{\text{C}_\text{v}} =(\frac{7}{5})\text{R}$ For non rigid diatomic molecules they have additional mode of vibrations therefore$\gamma=\frac{\text{C}_\text{p}}{\text{C}_\text{v}}=\frac{9}{7}$
Polyatomic Gases: In general a polyatomic molecule has 3 translational, 3 rotational degrees of freedom and a certain number (f) of vibrational modes. According to the law of equipartition of energy, it is easily seen that one mole of such a gas has Cv = (3 + f) R and Cp = (4 + f) R and $\gamma=\frac{(4 + \text{f})}{(3+\text{f})}$$\frac{5}{3}$
$\frac{7}{5}$
$\frac{9}{5}$
$\frac{5}{3}$
$\frac{7}{5}$
$\frac{9}{7}$

| Substance | Atomic Mass(u) | Density (103kgm-3) |
| Carbon (diamond) Gold Nitrogen (liquid) Lithium Fluorine (liquid) | 12.01 197.00 14.01 6.94 19.00 | 2.22 19.32 1.00 0.53 1.14 |


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