- ASulphuric acid is formed
- BA clear solution is formed
- ✓A sulphur is precipitated
- DNo change observed
$\,\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}
\end{array}} \\
{HO - S - O - O - S - OH} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}
\end{array}\,$ $+2 \mathrm{HOH} \rightarrow 2 \mathrm{H}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}$
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$(I)$ $ZnCl_2$ is ionic whereas $CdCl_2$ and $HgCl_2$ are covalent
$(II)$ $Zn$ and $Cd$ dissolves in dilute acid $(HCl)$ liberating $H_2$ but $Hg$ can not
$(III)$ $Zn$ and $Cd$ forming with ppt. of $Zn(OH)_2$ and $Cd(OH)_2$ but $Hg$ forms coloured ppt. of
$(IV)$ all from $A_2^{2+}$ type ion
$M\left( s \right) + 2{H^ + }\left( {1M} \right) \to {H_2}\left( {1atm} \right) + {M^{2 + }}\left( {0.1M} \right)$
is $1.5\,V$. The standard reduction potential for $M^{2+}/M(s)$ couple is ............. $\mathrm{V}$

$(i)\,\,KIO_3$ $(ii)\,\,KI$
$(iii)\,\,I_2$ $(iv)\,\, HI$