MCQ
When $S{O_2}$ is passed through acidified solution of ${H_2}S$
- A${H_2}S{O_4}$ is formed
- B${H_2}S{O_3}$ is formed
- ✓Sulphur is precipitated
- DNone of these
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$IO_3^-+ aI^-+ bH^+ \to cH_2O + dI_2$
$a, b, c, d$ respectively corresponds to

Phenol $\xrightarrow[{{H^ + }}]{{{\text{CHC}}{{\text{l}}_3}{\text{ /NaOH}}}}$ Salicyladehyde