MCQ
When the capillarly tube is inserted into water, the value of pressure difference between the points above and below the meniscus will be:
- A$\frac{4 T}{r}$
- ✓$\frac{2 T}{r}$
- C${2 T}{r}$
- D$4 T r$
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$[A]$ The midpoint of the bar will fall vertically downward
$[B]$ The trajectory of the point $\mathrm{A}$ is a parabola
$[C]$ Instantaneous torque about the point in contact with the floor is proportional to $\sin \theta$
$[D]$ When the bar makes an angle $\theta$ with the vertical, the displacement of its midpoint from the initial position is proportional to $(1-\cos \theta)$
$y = 2A\,\,\sin \,\left( {\frac{{2\pi ct}}{\lambda }} \right)\,\cos \,\,\,\left( {\frac{{2\pi x}}{\lambda }} \right)$
Which statement is not true?
