MCQ
When the distance between the charged particles is halved, the force between them becomes
- AOne-fourth
- BHalf
- CDouble
- ✓Four times
✓
Answer
Correct option: D.
Four times
d
(d)$F \propto \frac{1}{{{r^2}}}$; so when $r$ is halved the force becomes four times.
(d)$F \propto \frac{1}{{{r^2}}}$; so when $r$ is halved the force becomes four times.
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