When the temperature of an ideal gas is increased by $600 K$, the velocity of sound in the gas becomes $\sqrt 3 $ times the initial velocity in it. The initial temperature of the gas is .... $^oC$
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(b) By using $v = \sqrt {\frac{{\gamma RT}}{M}} \Rightarrow v \propto \sqrt T $
$\frac{{{v_2}}}{{{v_1}}} = \sqrt {\frac{{{T_2}}}{{{T_1}}}} = \sqrt {\frac{{T + 600}}{T}} = \sqrt 3 $
$\Rightarrow T = 300\,K\, = {27^o}C$
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