MCQ
When treated with ammoniacal cuprous chloride, which one among the following forms copper derivative
  • A
    ${C_2}{H_6}$
  • B
    ${C_2}{H_4}$
  • ${C_2}{H_2}$
  • D
    ${C_6}{H_6}$

Answer

Correct option: C.
${C_2}{H_2}$
c
(c) $2N{H_4}OH + C{u_2}C{l_2} \to 2CuOH + 2N{H_4}Cl$

$N{{H}_{4}}OH+CuOH\to \underset{\begin{smallmatrix} 
 \text{Diammine copper} \\ 
 \text{ }\left( I \right)\text{ hydroxide} 
\end{smallmatrix}}{\mathop{[Cu{{(N{{H}_{3}})}_{2}}]OH}}\,$

  $2[Cu{{(N{{H}_{3}})}_{2}}]\,OH+HC\equiv CH\to $ $\mathop {Cu - C \equiv C - Cu}\limits_{{\text{copper acetylide Red ppt}}{\text{.}}}  + 4N{H_3} + 2{H_2}O$

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