Question
Which among the curves shown in figure cannot possibly represent electrostatic field lines?
✓
Answer
- Field lines are wrongly drawn because electric field lines must be normal to the surface of the conductor at each point.
- Field lines are wrongly drawn because field lines cannot start from a negative charge.
- Field lines are correctly drawn, because they are originating from a positive charge.
- Field lines are wrongly drawn as the field lines cannot intersect.
- Field lines are wrongly drawn because they cannot form closed loops.
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We are given the following atomic masses:
$\begin{array}{l}{ }_{92}^{238} U=238.05079 u \\
{ }_2^4 H e=4.00260 u \\
{ }_{90}^{234} Th =234.04363 u \\
{ }_1^1 H=1.00783 u \\
{ }_{91}^{237} Pa=237.05121 u \end{array}$
Here the symbol Pa is for the element protactinium (Z = 91).
i. Calculate the energy released during the alpha decay of ${ }_{92}^{238} U$.
ii. Calculate the kinetic energy of the emitted $\alpha$-particles.
iii. Show that ${ }_{92}^{238} U$ can not spontaneously emit a proton.
→$\begin{array}{l}{ }_{92}^{238} U=238.05079 u \\
{ }_2^4 H e=4.00260 u \\
{ }_{90}^{234} Th =234.04363 u \\
{ }_1^1 H=1.00783 u \\
{ }_{91}^{237} Pa=237.05121 u \end{array}$
Here the symbol Pa is for the element protactinium (Z = 91).
i. Calculate the energy released during the alpha decay of ${ }_{92}^{238} U$.
ii. Calculate the kinetic energy of the emitted $\alpha$-particles.
iii. Show that ${ }_{92}^{238} U$ can not spontaneously emit a proton.
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