MCQ
Which bond angle $\theta $ gives maximum dipole moment for triatomic molecule $XY_2$
- A$\theta = {90^o}$
- ✓$\theta = {120^o}$
- C$\theta = {180^o}$
- DBoth $B$ and $C$
The dipole moment of two dipoles inclined at an angle $\theta$ is given by the equation
$\mu=\sqrt{X^2+Y^2+2 X Y \cos \theta}$
$\cos 90^{\circ}=0$. Since the angle increases from $90-180$, the value of $\cos \theta$ becomes more and more $-ve$ and hence resultant decreases. Thus, dipole moment is maximum when $\theta=90^{\circ}$
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| Column $I$ | Column $II$ |
| $(a)\,XeO_6^{-4}$ | $(P)$ Tetrahedral |
| $(b)\,ClO_2$ | $(Q)\,V-$ Shape |
| $(c)\,NH_4^+$ | $(R)$ Trigonal Bipyramidal |
| $(d)\,XeO_3F_2$ | $(S)$ Octahedral |