MCQ
Which bond angle $\theta $ would result in the maximum dipole moment for triatomic molecule $XY_2$ shown below


- ✓$\theta = 90^o$
- B$\theta = 120^o$
- C$\theta = 150^o$
- D$\theta = 180^o$

Since the angle increases from $90-180,$ the value of $\cos \theta$ becomes more and more -ve and hence resultant decreases, thus dipole moment is maximum when $\theta=90^{\circ}$.
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Above conversion can be achieved by
$O(g) + e^- = O^-(g)$ $\Delta {H_{eg}} = - 142\,kJ\,mo{l^{ - 1}}$
$O^-(g) + e^- = O^{2-}(g)$ $\Delta {H_{eg}} = +844\,kJ\,mo{l^{ - 1}}$
This is because
