The reaction $C{H_3}CH = C{H_2}\mathop {\xrightarrow{{(CO + {H_2})}}}\limits_{{H^{^ + }}} C{H_3} - \mathop {\mathop {CH - C{H_3}}\limits_{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \,\,\,\,\,}\limits_{COOH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \,\,$is known as
→$CsOH + HCl \to CsCl + H_2O, \Delta H = -13.4\, K\, cal/mol, CsOH + HA \to$ $CsA + H_2O$ , $\Delta H= -10.4\, K\, cal/mol$ Then calculate $'\Delta H'$ ionisation of $HA$......$K\, cal$
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