MCQ
Which combination gives maximum number of products ?
- A$P_4+SOCl_2$
- B$P_4+SO_2Cl_2$
- ✓$XeF_4+H_2O$
- D$NH_4NO_3 +Zn +$ Excess $NaOH$
$(b)$ $P_{4}+S O_{2} C l_{2} \longrightarrow P Cl_{5}+S O_{2}$
$(c)$ $\mathrm{XeF}_{4}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{Xe}+\mathrm{XeO}_{3}+\mathrm{HF}+\mathrm{O}_{2}$
$(d)$ $N H_{4} N O_{3}+Z n+\,e x c e s s\, N a O H \longrightarrow N H_{3} \uparrow+N a Zn O_{2}+H_{2} O$
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Reason : Alcohols leading to conjugated alkenes are dehydrated to a greater extent
$CuI_{(s)} + e^{\circleddash} \to Cu_{(s)} + I^{\circleddash}_{(aq)}$ ; $E^o = -0.17\, V$
$Zn^{+2}_{(aq)} + 2e^{\circleddash} \to Zn_{(s)}$ ; $E^o = -0.76\, V$
