STD 12 - 4. d and f- block elements — NEET STD 11 Science — Question

$\begin{array}{*{20}{c}}
  {Ph - C{H_2} - CH - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,} 
\end{array}$ $>$ $\begin{array}{*{20}{c}}
  {Me - C{H_2} - CH - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,} 
\end{array}$

${N_2}(g)\, + 3{H_2}(g)\, \rightleftharpoons \,2N{H_3}(g)$ 

The equilibrium constant of the above reaction is $K_3$. If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume that $P_{NH_3}<\,< P_{total}$ at equilibrium)

$\frac{2}{3}A{l_2}{O_3} \to \frac{4}{3}Al + {O_2},{\Delta _r}G =  + 940\,kJ\,mo{l^{ - 1}}$

The potential difference needed for the electrolytic reduction of aluminium oxide ............... $\mathrm{V}$