- ✓${N_2}$
- B${H_2}$
- C${O_2}$
- D$N{H_3}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{C{H_3} - CH - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{\Delta }[Y]$
$[Y]$ will be :
(Image)
Pre-exponential factors for the forward and backward reactions are $10^{15} \mathrm{~s}^{-1}$ and $10^{11} \mathrm{~s}^{-1}$, respectively. If the value of $\log \mathrm{K}$ for the reaction at $500 \mathrm{~K}$ is $6$ , the value of $\left|\log \mathrm{k}_{\mathrm{b}}\right|$ at $250 \mathrm{~K}$ is $\qquad$
$[\mathrm{K}=$ equilibrium constant of the reaction
$\mathrm{k}_{\mathrm{f}}=$ rate constant of forward reaction
$\mathrm{k}_{\mathrm{b}}=$ rate constant of backward reaction]
Given $\left( E _{ Cu ^{2+} / Cu ^{+}}^{0}=0.16 V \right.$ $E _{ Cu ^{+} / Cu }^{0}=0.52 V$$\left.\frac{ RT }{ F }=0.025\right)$
