MCQ
Which is the correct alternate for hydrolysis constant of $N{H_4}CN$
- A$\sqrt {\frac{{{K_w}}}{{{K_a}}}} $
- ✓$\frac{{{K_w}}}{{{K_a} \times {K_b}}}$
- C$\sqrt {\frac{{{K_b}}}{c}} $
- D$\frac{{{K_a}}}{{{K_b}}}$
✓
Answer
Correct option: B.
$\frac{{{K_w}}}{{{K_a} \times {K_b}}}$
(b)$N{H_4}CN$ is a salt of weak acid and weak base and thus for it
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In which of the following reactions product formed is same ?
In DNA, C joins with ......... base by ......... hydrogen bonds.
$20\,ml$ of $0.5\,N\,HCl$ and $35\,ml$ of $0.1\,N\,NaOH$ are mixed. The resulting solution will
→The bond order and magnetic behaviour of $\mathrm{O}_{2}^{-}$ion are, respectively:
→Complex compounds $(s)$ which is optical active and does not depend upon the orientation of the ligands around metal cation :
→$(i)\, [CoCl_3 (NH_3)_3]$ $(ii)\, [Co(en)_3]Cl_3$
$(iii)\, [Co(C_2O_4)_2(NH_3)_2]^-$ $(iv)\, [CrCl_2(NH_3)_2(en)]^+$
In the cobalt-carbonyl complex: $\left[ Co _{2}( CO )_{8}\right]$, number of $Co-Co$ bonds is " $X$ " and terminal $CO$ ligands is $" Y ".$ $X + Y =...... .$
→For a reaction scheme. $A\xrightarrow{{{k_1}}}B\xrightarrow{{{k_2}}}C$ if the rate of formation of $B$ is set to be zero then the concentration of $B$ is given by
→Calculate $(q)$ when $0.75$ mole of an ideal gas expands isothermally and reversibly at $27\,^oC$ from a volume of $15$ litre to $25$ litre
→(Given $\log 5 = 0.70, \log 3 = 0.48$)
...... $joule$
Chloroform when treated with aniline and alcoholic $KOH$ gives
→An isomer of ${C_3}{H_6}C{l_2}$ on boiling with aqueous $KOH$ gives acetone. Hence, the isomer is
→