Question
Which of the following are meso compound?

Answer

d

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The correct order of their reactivity towards hydrolysis at room temperature is :
Which one of the following compounds in aqueous solution gives a white precipitate with perchloric acid
The oxidation number of sulphur in ${H_2}{S_2}{O_7}$ and iron in ${K_4}Fe{(CN)_6}$ is respectively
Mercury is transported in metal containers made of
Given below are two statements, one is labelled as Assertion $A$ and the other is labelled as Reason $R$

Assertion $A :$- Carbon forms two important oxides $- CO$ and $CO _2 . CO$ is neutral whereas $CO _2$ is acidic in nature.

Reason $R :$- $CO _2$ can combine with water in a limited way to form carbonic acid, while $CO$ is sparingly soluble in water.

In the light of the above statements, choose the most appropriate answer from the options given below :-

$CrCl _3 \cdot xNH _3$ can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of $0.558^{\circ} C$. Assuming $100 \%$ ionisation of this complex and coordination number of Cr is 6 , the complex will be (Given $K _{ f }=1.86 K kg mol ^{-1}$ )
Invar, an alloy of $ Fe$  and $ Ni $ is used in watches and meter scale, its characteristic property is
The freezing point of one molal $NaCl$ solution assuming $NaCl$ to be $100\% $ dissociated in water is  ............ $^oC$. (molal depression constant $= 1.86$)
The two electrons occupying the same orbital are distinguished by:
Redox reactions play a pivotal role in chemistry and biology. The values of standard redox potential ( $\mathrm{E}^{\circ}$ ) of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below are a set of half-cell reactions (acidic medium) along with their $E^{\circ}$ ($V$ with respect to normal hydrogen electrode) values. 

$\mathrm{I}_2+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{I}\ \ \   \mathrm{E}^{\circ}=0.54 $

$\mathrm{Cl}_2+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cl}^{-} \ \ \  \mathrm{E}^{\circ}=1.36 $

$\mathrm{Mn}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+} \ \ \  \mathrm{E}^{\circ}=1.50 $

$\mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+} \ \ \  \mathrm{E}^{\circ}=0.77 $

$\mathrm{O}_2+4 \mathrm{H}^{+}+4 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_2 \mathrm{O} \ \ \  \mathrm{E}^{\circ}=1.23$

$1.$ Among the following, identify the correct statement.

$(A)$ Chloride ion is oxidized by $\mathrm{O}_2$

$(B)$ $\mathrm{Fe}^{2+}$ is oxidized by iodine

$(C)$ Iodide ion is oxidized by chlorine

$(D)$ $\mathrm{Mn}^{2+}$ is oxidized by chlorine

$2.$ While $\mathrm{Fe}^{3+}$ is stable, $\mathrm{Mn}^{3+}$ is not stable in acid solution because

$(A)$ $\mathrm{O}_2$ oxidises $\mathrm{Mn}^{2+}$ to $\mathrm{Mn}^{3+}$

$(B)$ $\mathrm{O}_2$ oxidises both $\mathrm{Mn}^{2+}$ and $\mathrm{Fe}^{2+}$ to $\mathrm{Fe}^{3+}$

$(C)$ $\mathrm{Fe}^{3+}$ oxidizes $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$

$(D)$ $\mathrm{Mn}^{3+}$ oxidises $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$

$3.$ Sodium fusion extract, obtained from aniline, on treatment with iron $(II)$ sulphate and $\mathrm{H}_2 \mathrm{SO}_4$ in presence of air gives a Prussian blue precipitate. The blue colour is due to the formation of

$(A)$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$ $(B)$ $\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$

$(C)$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$ $(D)$ $\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$

Give the answer question $1,2$ and $3.$