MCQ
$CrCl _3 \cdot xNH _3$ can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of $0.558^{\circ} C$. Assuming $100 \%$ ionisation of this complex and coordination number of Cr is 6 , the complex will be (Given $K _{ f }=1.86 K kg mol ^{-1}$ )
- A$\left[ Cr \left( NH _3\right)_6\right] Cl _3$
- B$\left[ Cr \left( NH _3\right)_4 Cl _2\right] Cl$
- ✓$\left[ Cr \left( NH _3\right)_5 Cl \right] Cl _2$
- D$\left[ Cr \left( NH _3\right)_3 Cl _3\right]$
