MCQ
- A(I) and (II)
- B(II) and (III)
- C(III) and (IV)
- D(II) and (IV)
Explanation:
(III) and (IV) are enantiomers and have the same physical and chemical properties.
So they will have the same vapour pressure.
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$C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,}{\mathop{\overset{OH}{\mathop{\overset{|\,\,\,\,}{\mathop{C-}}\,}}\,}}\,}}\,C{{H}_{2}}-\underset{C{{H}_{3}}\,}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{CH-}}\,}}\,C{{H}_{3}}$
The product of the above reaction is
(Rounded off to the nearest integer)
(Mass of $Li ^{3+}=8.3$ mass of proton)