MCQ
Which of the following electronic configuration represent representative elements
- A$ns^{1,2}\,\,np^{1-5}$
- ✓$ns^{1,2}\,\,np^{0-5}$
- C$ns^{1,2}\,\,np^{0-6}$
- D$ns^{1,2}\,\,np^{1-6}$
✓
Answer
Correct option: B.
$ns^{1,2}\,\,np^{0-5}$
b
Representative elements are $s$ and $p-$ block element.
Representative elements are $s$ and $p-$ block element.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
For the hypothetical reaction
→${A_2}\left( g \right) + {B_2}\left( g \right) \rightleftharpoons 2AB\left( g \right)$
${\Delta _r}{G^o}$ and ${\Delta _r}{S^o}$ are $20\, kJ/mol$ and $-20\, JK^{-1}\, mol^{-1}$ respectively at $200\, K$.
If ${\Delta _r}{C_P}$ is $20\, JK^{-1}\, mol^{-1}$ then ${\Delta _r}{H^o}$ at $400\, K$ is.....$kJ/mol$
$CrO_4^{2-}$ (yellow) changes to $Cr_2O_7^{2-}$ (orange) in $pH = x$ and vice-versa in $pH = y$. Hence, $x$ and $y$ are
→Newman projections $P , Q , R$ and $S$ are shown below :
→Which one of the following options represents identical molecules?
Two aliphatic aldehydes $\mathrm{P}$ and $\mathrm{Q}$ react in the presence of aqueous $\mathrm{K}_2 \mathrm{CO}_3$ to give compound $\mathrm{R}$, which upon treatment with $\mathrm{HCN}$ provides compound $\mathrm{S}$. On acidification and heating, $\mathrm{S}$ gives the product shown below: $Image$
→$1.$ The compounds $\mathrm{P}$ and $\mathrm{Q}$ respectively are
MCQ $Image$
$2.$ The compound $R$ is
MCQ $Image$
$3.$ The compound $\mathrm{S}$ is
MCQ $Image$
Give the answer question $1,2$ and $3.$
Deep sea divers used to respirate is a mixture of
$417\ g\ PCl_5(s)$ is kept in an open container where it reacts with moisture from air to form $POCl_3(s)$ & $HCl(g)$ . Few hours later the solid left in the container weighted only $395\ g$ . The percentage of $PCl_5$ converted to $POCl_3$ is : .............. $\%$ ( $P = 31$ , $Cl = 35.5$ , $O = 16$ , $H = 1$ )
→Match the colum
→| Column $-I$ | Column $-II$ |
| (Atomic number) | (Position of element in Periodic table) |
| $(A)$ $Z = 37$ | $(P)$ $p-$ block |
| $(B)$ $Z = 42$ | $(Q)$ $f-$ block |
| $(C)$ $Z = 34$ | $(R)$ $d-$ block |
| $(D)$ $Z = 92$ | $(S)$ $s-$ block |
What will be the major product in the following mononitration reaction ?
Strongest acid is
A mixture of benzene and aniline can be separated by