MCQ
Which of the following equations has $x = 2$ as a solution?
- A$x + 2 = 5$
- ✓$x - 2 = 0$
- C$2x + 1 = 0$
- D$x + 3 = 6$
✓
Answer
Correct option: B.
$x - 2 = 0$
To get solution as $x = 2$, solve each equation.
For option $(a),$
$x + 2 = 5$
$\Rightarrow x = 5 - 2$ [transposing $+2$ to $RHS$]
$\Rightarrow x = 3$
For option $(b)$,
$x - 2 = 0$
$\Rightarrow x = 2$ [transposing $-2$ to $RHS$]
For option $(c)$,
$2x + 1 = 0$
$2x = -1$ [transposing $+1$ to $RHS$]
$\Rightarrow\frac{2\text{x}}{2}=\frac{-1}{2}$ [dividing both sides by $2$]
$\Rightarrow\text{x}=\frac{-1}{2}$
For option $(d)$,
$\Rightarrow x + 3 = 6$
$\Rightarrow x = 6 - 3$ [transposing $+3$ to $RHS$]
$\Rightarrow x = 3$
Therefore, we get $x = 2$ as a solution in option $(b)$ only.
Hence, $(b)$ is correct option.
For option $(a),$
$x + 2 = 5$
$\Rightarrow x = 5 - 2$ [transposing $+2$ to $RHS$]
$\Rightarrow x = 3$
For option $(b)$,
$x - 2 = 0$
$\Rightarrow x = 2$ [transposing $-2$ to $RHS$]
For option $(c)$,
$2x + 1 = 0$
$2x = -1$ [transposing $+1$ to $RHS$]
$\Rightarrow\frac{2\text{x}}{2}=\frac{-1}{2}$ [dividing both sides by $2$]
$\Rightarrow\text{x}=\frac{-1}{2}$
For option $(d)$,
$\Rightarrow x + 3 = 6$
$\Rightarrow x = 6 - 3$ [transposing $+3$ to $RHS$]
$\Rightarrow x = 3$
Therefore, we get $x = 2$ as a solution in option $(b)$ only.
Hence, $(b)$ is correct option.
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