$5 \mathrm{BiO}_{3}^{-}+14 \mathrm{H}^{+}+2 \mathrm{Mn}^{2+} \rightarrow 5 \mathrm{Bi}^{3+}+7 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{MnO}_{4}^{-}$
In this equation, the number of atoms of each element on the left side are equal to the number of atoms on the right side.
The charges are also balanced on the two sides of equation.
Hence, option B is the correct answer.
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$\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{H}_{3}}C-C-CH=C{{H}_{2}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\,\, \\
\end{matrix}$
