Download App

STD 11 - 4. Chemical bonding and molecular structure — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 4. Chemical bonding and molecular structure4 Marks
MCQ
Which of the following has $p\pi - d\pi $ bonding
  • A
    $NO_3^ - $
  • B
    $CO_3^{ - 2}$
  • C
    $BO_3^{ - 3}$
  • ✓
    $SO_3^{ - 2}$
✓

Answer

Correct option: D.
$SO_3^{ - 2}$
(d)$:\mathop O\limits^{.\,\,.} = \mathop {\mathop {S\,}\limits_{||\,\,\,\,} }\limits_{\mathop {O:}\limits_{.\,\,.\,\,} } = \mathop O\limits^{.\,\,.} :$ $5$ atoms has $12$ electrons in its outermost shell.

One $(S - O)\pi $ bond will be $(p-p)$ $\pi$ bond while two $(S - O)\pi $ bond will be $(p-d)$ $\pi$ bond.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

On halogenation, an alkane gives only one monohalogenated product. The alkane  may be
→
Of the ions $Z{n^{2 + }},$ $N{i^{2 + }}$ and $C{r^{3 + }}$[atomic number of $Zn = 30,$ $Ni = 28,$ $Cr = 24$
→
One mole of a non-ideal gas undergoes a change of state ($2.0\, atm$, $3.0\, L$ , $95 \,K$ ) $\rightarrow $($4.0\, atm$ , $5.0\, L$ , $245\, K )$ with a change in internal energy, $\Delta U =30.0 \,L$ $atm$. The change in enthalpy $\Delta H$ of the process in $L\,atm$ is.
→
The active mass of $64\, gm$ of $HI$ in a two litre flask would be
→
$H_3BO_3$ is
→
Rate law for a reaction between $A$ and $B$ is given by
$\mathrm{R}=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}}$
If concentration of A is doubled and concentration of $B$ is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction $\left(\frac{r_{2}}{r_{1}}\right)$ is
→
In equimolar solution of glucose, $NaCl$ and $BaC{l_2}$, the order of osmotic pressure is as follow
→
The final product formed when acetaldehyde is reduced with sodium and alcohol is
→
Thallium shows different oxidation states because
→
Empirical formula of a compound is ${C_2}{H_5}O$ and its molecular weight is $90$. Molecular formula of the compound is
→