
Assertion $(A)$ : Experimental reaction of $CH _{3} Cl$ with aniline and anhydrous $AlCl _{3}$ does not give $o$ and $p-methylaniline$.
Reason $(R)$ : The - $NH _{2}$ group of aniline becomes deactivating because of salt formation with anhydrous $AlCl _{3}$ and hence yields $m$-methyl aniline as the product.
In the light of the above statements, choose the most appropriate answer from the options given below.
$CH_3CH_2Cl \xrightarrow{NaCN}(i)\xrightarrow{Ni/{{H}_{2}}}(ii)\xrightarrow{acetic\,anhydride}(iii)$ , Product $(iii)$ is

Consider the above reaction. The percentage yield of amide product is ...... . (Round off to the Nearest Integer). (Given : Atomic mass : $C : 12.0\, u , H : 1.0 \,u,N : 14.0\, u , O : 16.0\, u , Cl : 35.5\, u )$
