- ✓Molarity
- BMole fraction
- CWeight percentage
- DMolality
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$\begin{matrix}
\begin{matrix}
\,\,\,\,\,C{{H}_{3}} \\
| \\
\end{matrix}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}C{{H}_{2}}OH \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ $\xrightarrow[{{H_2}O,heat}]{{{K_2}C{r_2}{O_7};{H_2}S{O_4}}}A$ $\xrightarrow{{SOC{l_2}}}B\xrightarrow[{(2{\kern 1pt} mole)}]{{{{(C{H_3})}_2}NH}}C$ $\xrightarrow[{2.{\kern 1pt} {H_2}O}]{{\begin{array}{*{20}{c}}
{1.{\kern 1pt} LiAl{H_4}} \\
{diethyl{\kern 1pt} {\kern 1pt} ether}
\end{array}}}D$

For the cell $\mathrm{Cu}(\mathrm{s})\left|\mathrm{Cu}^{2+}(\mathrm{aq})(0.01 \mathrm{M}) \| \mathrm{Ag}^{+}(\mathrm{aq})(0.001 \mathrm{M})\right| \mathrm{Ag}(\mathrm{s})$ the cell potential $=.....\times 10^{-2} \mathrm{~V}$
(Round off to the Nearest Integer).
[Use: $\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059$ ]