MCQ
Which of the following is equal to 'x'?
- A$(\sqrt{\text{x}^3})^{\frac{2}{3}}$
- B$\text{x}^{\frac{12}{7}}\times\text{x}^{\frac{7}{12}}$
- C$\text{x}^{\frac{12}{7}}-\text{x}^{\frac{5}{12}}$
- D$\sqrt[12]{(\text{x}^4)^{\frac{1}{3}}}$
✓
Answer
- $(\sqrt{\text{x}^3})^{\frac{2}{3}}$
Solution:
$(\sqrt{\text{x}^3})^{\frac{2}{3}}$
$=(\text{x}\frac{3}{2})^{\frac{2}{3}}$
$=\text{x}$
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