Amines — Chemistry STD 12 Science — Question

Time                                 Rate (mole $litre^{-1}\,sec^{ -1}$ )

$0$                                        $2.8 \times {10^{ - 2}}$

$10$                                      $2.78 \times {10^{ - 2}}$

$20 $                                     $2.81 \times {10^{ - 2}}$

$30$                                       $2.79 \times {10^{ - 2}}$

The reaction is

$2 Fe _{( s )}+ O _{2( g )}+4 H _{( aq )}^{+} \rightarrow 2 Fe _{( aq )}^{2^{+}}+2 H _2 O ( l ) \quad E ^{\circ}=1.67 V$, At $\left[ Fe ^{2+}\right]=10^{-3} M , P \left( O _2\right)=0.1$ atm and $pH =3$, the cell potential at $25^{\circ} C$ is

$N{O_2} + {F_2}\xrightarrow{{slow}}N{O_2}F + F$

$N{O_2} + F\xrightarrow{{fast}}N{O_2}F$

Thus rate expression of the above reaction can be written as