MCQ
Which of the following is not electrophile
- ✓$C{H_3} - C{H_2} - \mathop O\limits^ \oplus {H_2}$
- B$C{H_3} - Br$
- C$Br_2$
- D$CH_3-CH=CH_2$
✓
Answer
Correct option: A.
$C{H_3} - C{H_2} - \mathop O\limits^ \oplus {H_2}$
a
The order of reactivity of the benzene rings toward the electrophilic substitution when it is substituted with a activating group increases as the substituents on the ring are groups that donate electrons. $- CH _3$ is an activating group which makes benzene more reactive towards electrophile while- $COOH$ is a deactivating group which makes it less reactive.
The order of reactivity of the benzene rings toward the electrophilic substitution when it is substituted with a activating group increases as the substituents on the ring are groups that donate electrons. $- CH _3$ is an activating group which makes benzene more reactive towards electrophile while- $COOH$ is a deactivating group which makes it less reactive.
The order reactivity towards the eletrophilic substitution of the compounds Toluene($I$)$\,>\,$ benzene($II$) $\,>\,$ Benzoicacid($III$)
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which order is correct for the decreasing reactivity to ring monobromination of the following compounds
In which of the following arrangements, the sequence is not strictly according to the property written against it ?
$S{O_2} + {H_2}S \to $ product. the final product is
→Final product formed on reduction of glycerol by hydroiodic acid is
$Y$ is
→In the estimation of bromine, $0.5\, g$ of an organic compound gave $0.40\, g$ of silver bromide. The percentage of bromine in the given compound is $.....\,\%$ (nearest integer)
→(Relative atomic masses of $Ag$ and $Br$ are $108\, u$ and $80\, u$, respectively).
Which does not undergo comproportionation reaction ?
Among the given compounds, the correct order of enol content is
If the nitrogen atom had electronic configuration $1s^7,$ it would have energy lower than of the normal ground state configuration $1s^2 ,2s^2 ,2 p^3$ because the electron would be closer to the nucleus. Yet $1s^7$ is not observed because it violates
→Which is obtained on treating phenol, with concentrated $HN{O_3}$
→