MCQ
Which of the following molecule has lowest bond angle
- A$PH_3$
- B$H_2S$
- C$H_2O$
- ✓$SbH_3$
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Given $\mathrm{R}=8.31\, \mathrm{~J} \,\mathrm{~K}^{-1} \,\mathrm{~mol}^{-1} ; \log 6.36 \times 10^{-3}=-2.19$ $\left.10^{-4.79}=1.62 \times 10^{-5}\right]$