- AElectric flux
- BElectric potential
- CElectric potential energy
- ✓Electric intensity
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A particle is moving in a uniform magnetic field, then
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(a) Its momentum changes but total energy remains the same |
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(b) Both momentum and total energy remain the same |
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(c) Both will change |
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(d) Total energy changes but momentum remains the same |
The binding energy of nucleus is a measure of its
| (a) Charge | (b) Mass | (c) Momentum | (d) Stability |
Fraunhofer lines are produced by
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(a) The element present in the photosphere of sun |
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(b) The elements present in the chromosphere of the sun |
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(c) The vapour of the element present in the chromosphere of the sun |
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(d) The carbon dioxide present in the atmosphere |
Resistance of a voltameter is 2Ω, it is connected in series to a battery of 10 V through a resistance of 3Ω. In a certain time mass deposited on cathode is 1 gm. Now the voltameter and the 3Ω resistance are connected in parallel with the battery. Increase in the deposited mass on cathode in the same time will be
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(a) 0 |
(b) 1.5 gm |
(c) 2.5 gm |
(d) 2 gm |
Energy bands in solids are a consequence of
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(a) Ohm’s Law |
(b) Pauli’s exclusion principle |
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(c) Bohr’s theory |
(d) Heisenberg’s uncertainty principle |
Match List I with List II and select the correct answer using the codes given below the lists :
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List I (Position of the object) |
List II (Magnification) |
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(I) An object is placed at focus before a convex mirror |
(A) Magnification is -∞ |
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(II) An object is placed at centre of curvature before a concave mirror |
(B) Magnification is 0.5 |
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(III) An object is placed at focus before a concave mirror |
(C) Magnification is +1 |
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(IV) An object is placed at centre of curvature before a convex mirror |
(D) Magnification is -1 |
|
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(E) Magnification is 0.33 |
Codes :
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(a) I-B, II-D, III-A, IV-E |
(b) I-A, II-D, III-C, IV-B |
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(c) I-C, II-B, III-A, IV-E |
(d) I-B, II-E, III-D, IV-C |
X-rays cannot be deflected by means of an ordinary grating due to
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(a) Large wavelength |
(b) High speed |
(c) Short wavelength |
(d) None of these |
For a given surface the Gauss's law is stated as From this we can conclude that
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(a) E is necessarily zero on the surface |
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(b) E is perpendicular to the surface at every point |
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(c) The total flux through the surface is zero |
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(d) The flux is only going out of the surface |