Question
Which of the following sequences are arithmetic progressions. For those which are arithmetic progressions, find out the common difference.
$3, 6, 12, 24, .....$
$3, 6, 12, 24, .....$
✓
Answer
In the given problem, we are given various sequences.
We need to find out that the given sequences are an A.P. of not and then find its common difference (d).
$3, 6, 12, 24, .....$
Here,
First term $(a) = 3$
$ a_1=6 $
$ a_2=12$
Now, for the given to sequance to be an A.P, Common difference $(\mathrm{d})=\mathrm{a}_1-\mathrm{a}=\mathrm{a}_2-\mathrm{a}_1$
Here,
$ a_1-a=6-3$
$ =3$
Also,
$ a_2-a_1=12-6 $
$ =6$
Since $\text{a}_1-\text{a}\neq\text{a}_2-\text{a}_1$
Hence, the given sequence is not an A.P.
We need to find out that the given sequences are an A.P. of not and then find its common difference (d).
$3, 6, 12, 24, .....$
Here,
First term $(a) = 3$
$ a_1=6 $
$ a_2=12$
Now, for the given to sequance to be an A.P, Common difference $(\mathrm{d})=\mathrm{a}_1-\mathrm{a}=\mathrm{a}_2-\mathrm{a}_1$
Here,
$ a_1-a=6-3$
$ =3$
Also,
$ a_2-a_1=12-6 $
$ =6$
Since $\text{a}_1-\text{a}\neq\text{a}_2-\text{a}_1$
Hence, the given sequence is not an A.P.
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