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As shown in the figure, the uniform magnetic field between the two identical plates is $B$. There is a hole in plate. If through this hole a particle of charge $q$, mass $m$ and energy $E$ enters this magnetic field, then the particle will not collide with the upper plate provided
A $50\, ohm$ galvanometer gets full scale deflection when a current of $0.01\, A$ passes through the coil. When it is converted to a $10\, A$ ammeter, the shunt resistance is ........... $\Omega $
The magnitude of the magnetic field at the centre of an equilateral triangular loop of side $1\,m$ which is carrying a current of $10\,A$ is:......$\mu T$ [Take $\mu _0 = 4\pi \times 10^{-7}\,NA^{-2}$]
An infinitely long straight conductor carries a current of $5 \,\mathrm{~A}$ as shown. An electron is moving with a speed of $10^{5} \, \mathrm{~m} / \mathrm{s}$ parallel to the conductor. The perpendicular distance between the electron and the conductor is $20 \, \mathrm{~cm}$ at an instant. Calculate the magnitude of the force experienced by the electron at that instant in $\times 10^{-20} \,N$
A galvanometer has a resistance of $20\,\Omega$ and reads full-scale when $0.2\, V$ is applied across it. To convert it into a $10\, A$ ammeter, the galvanometer coil should have a
A straight wire carrying a current of $14\,A$ is bent into a semicircular are of radius $2.2\,cm$ as shown in the figure. The magnetic field produced by the current at the centre $(O)$ of the arc. is $.........\,\times 10^{-4}\, T$
An electron is moving along the positive $X$$-$axis. You want to apply a magnetic field for a short time so that the electron may reverse its direction and move parallel to the negative $X$$-$axis. This can be done by applying the magnetic field along
An insulating rod of length $l$ carries a charge $q$ distributed uniformly on it. The rod is pivoted at an end and is rotated at a frequency $f$ about a fixed perpendicular $t$ axis. The magnetic moment of the system is
Two circular coils $1$ and $2$ are made from the same wire but the radius of the $1^{st}$ coil is twice that of the $2^{nd}$ coil. What is the ratio of potential difference in volts should be applied across them so that the magnetic field at their centres is the same?